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I am not sure what is meant by exponent notation and therefore how to answer this question is baffling me.

Rewrite this in exponent notation:

$\sqrt[3]{x^2y(z-X)^5}$

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Example: $\sqrt[7]{x^2y^3}=x^{2/7}y^{3/7}$. Also, $\sqrt[5]{x/y^2}=x^{1/5}y^{-2/5}$. –  André Nicolas Jul 27 '12 at 22:27

1 Answer 1

up vote 3 down vote accepted

Oh so it is literally just a case of doing this?

$({x^2y(z-X)^5})^\frac{1}{3}$

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I think they want $x^{2/3}y^{1/3}(z-X)^{5/3}$. But what you wrote is technically right. –  André Nicolas Jul 27 '12 at 22:36
    
I should simplify further like you did, as a rule, yes? –  Magpie Jul 27 '12 at 22:37
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The grader makes up the rules! I gave my reading of what is expected. There is a chance your version would be marked wrong. It isn't. –  André Nicolas Jul 27 '12 at 22:39
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If this is a multiple choice question, it should be easy to spot right choice. If not, there are many equivalent expressions in exponent notation: yours, the one I gave earlier, others. –  André Nicolas Jul 27 '12 at 22:52
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@Magpie : instead of $\frac {x-1}{x^{\frac {1}{2}}}$, would you prefer $(x-1)x^{-\frac{1}{2}}$ or instead of that $x^{\frac{1}{2}}-x^{-\frac{1}{2}}$ or (just to give them something to think about :) $(x^{\frac{1}{4}}-x^{-\frac{1}{4}})(x^{\frac{1}{4}}+x^{-\frac{1}{4}})$ ( they are all the same(please check for yourself, hope I didnt make a mistake). –  Arjang Jul 27 '12 at 23:00

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