# Lipschitz Functions

Does uniform convergence on a closed and bounded interval preserve Lipschitz functions?
(Assume that the sequence of functions has a common Lipschitz constant $K$).

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 I must be missing something obvious, but won't ordinary pointwise convergence preserve $K$-Lipschitz functions? – Jesse Madnick Jul 26 '12 at 4:10 @JesseMadnickHow are you proving it ? – Roger Jul 26 '12 at 4:18

If $f_n\colon [a,b] \to \mathbb{R}$ each satisfy $|f_n(x) - f_n(y)| \leq K|x-y|$ for all $x, y \in [a,b]$, then just by taking the (pointwise) limit as $n \to \infty$, we obtain $|f(x) - f(y)| \leq K|x-y|$.
This reminds me of the following fact: If $\{f_n\}$ is a sequence of (uniformly) equicontinuous functions $[a,b]\to \mathbb{R}$, then $\{f_n\}$ converges pointwise if and only if $\{f_n\}$ converges uniformly.
 I have one question: does it hold also for Holder functions? I mean: is the pointwise limit of $\alpha$-Holder functions still $\alpha$-Holder? – Romeo Jul 26 '12 at 8:28 @Romen: If they have uniform Holder bounds, yes. The proof is basically the same as that Jesse gave above. – Willie Wong♦ Jul 26 '12 at 9:41 @Jesse Thanks . I thought that it is false ,so I was looking for a counterexample . So stupid of me ! – Roger Jul 26 '12 at 13:22