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The resulting metric topology corresponding to the norm given by: $\|f\| = \sup\limits_{x\in X} | f(x) |$ on $C^*(X)$ is called the uniform norm topology on $C^*(X)$. Show that, in uniform norm topology is uniform convergence of the functions.

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What have you tried? –  Alex Becker Jul 25 '12 at 2:16
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What does the $C^*$ indicate, as opposed to $C$? Bounded functions? I think your last sentence is missing some words too. It would be nice to add a whole new sentence or two saying what you've tried. I mean, take a convergent sequence $f_n \to f$ for $\|\,\|$ and try to show that the $f_n$ converge uniformly to $f$. Where do you get stuck? –  Dylan Moreland Jul 25 '12 at 2:23
    
@Dylan: yes. Bounded and continuous real-valued functions. See also this previous question. –  t.b. Jul 25 '12 at 2:28
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Standard notation for this is $C_b(X)$. –  ncmathsadist Jul 25 '12 at 2:37
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@ncmathsadist Both notations are standard, the $C^*(X)$ notation is common in the litterature on Stone-Cech compactification and Stone Spaces, for instance in Stone spaces by Peter T.Johnstone. –  Olivier Bégassat Jul 25 '12 at 2:59

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As I understand it, you are trying to show that if $C^*(X)$ is given the uniform norm topology, then if a sequence of functions on $C^*(X)$ converges, then it converges uniformly. So you started out taking a sequence $F_1, F_2,...$ of elements of $C^*(X)$, but these are functions of $X$, so you should not have written $F(f)$ where $f$ is in $C^*(X)$. But if you fix that mistake, then your answer is right. This question is really just a matter of getting the definitions right.

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I've taken Fn:C∗(X) --> R –  Sugata Adhya Jul 25 '12 at 5:55
    
But you're starting with a set of points of $C^*(X)$ that converge, right? And then trying to show that those functions converge uniformly? –  dc631 Jul 25 '12 at 5:58
    
I didn't start with points of C*(X). Do I've to do that? –  Sugata Adhya Jul 25 '12 at 6:01
    
I thought I need to choose a sequence Fn: C*(X) ---> R that converges uniformly to a F: C*(X) ---> R and then I've to show the convergence is uniform. That's what I thought. –  Sugata Adhya Jul 25 '12 at 6:03
    
I don't think so. You're trying to prove something about convergence of functions in $C^*(X)$. By that we mean a sequence of functions that converge in the uniform norm topology. You're trying to show that convergence in the uniform norm topology is the same as uniform convergence. Convergence of what in the uniform norm topology? Well, $C^*(X)$ is given the uniform norm topology. So convergence refers to this space. What does it mean for a sequence of elements of $C^*(X)$ to converge? –  dc631 Jul 25 '12 at 6:10

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