Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I need to know where I am going wrong since I am getting the wrong answer

12 litres of water are poured into an aquarium of $50$ cm length , $30$ cm breadth and $40$ cm Height.How high in cm will the water rise. (Ans 8 cm)

Edit: So I was making some very illogical assumptions however according to advice given which suggested that I keep the changing dimension value variable I got the answer which is

$1000cm^3$ = $50 \times 30 \times x$ so $x = \frac{1000}{1500}$. so $1$ litre has height $\frac{1000}{1500} = \frac {2}{3}$ so $12$ litres will give $12 \times \frac{2}{3} = 8 cm$

share|cite|improve this question
I think a good start would be to ask whatever led you to write $50\times30\times40=5\times3\times4$ when it's patently not so. – Gerry Myerson Jul 24 '12 at 10:53
I agree that does not make sense – MistyD Jul 24 '12 at 10:55
Tips on solving this problem ? – MistyD Jul 24 '12 at 10:56
Which dimension (length, breadth, height) changes when you pour in the water? This is where the $x$ should go. The other two stay constant, so you have $x\cdot C_1 \cdot C_2$, which should match $12\;l$. To make the match, you have to convert litres to $cm^3$... – draks ... Jul 24 '12 at 10:56
how did you get $12l$ ? – MistyD Jul 24 '12 at 11:01
up vote 2 down vote accepted

Congratulation: your answer is correct!

share|cite|improve this answer
You should have posted this as a CW answer, there is no real content in this and it only serves as a verification to the OP. – Asaf Karagila Jul 24 '12 at 14:01
@AsafKaragila Ok, but maybe you missed part of the story. Have a look at the comments and the revisions of the question. After alll, I'm still young and need the reputation...;-) – draks ... Jul 24 '12 at 14:40
draks, I saw that, and this is indeed what you should do when you solve something like that in the comments. However protocol suggests that if you didn't really answer beyond that, it's in good faith to make your answer CW. – Asaf Karagila Jul 24 '12 at 14:42
@AsafKaragila I'll promise I'll do next time... – draks ... Jul 24 '12 at 16:20

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.