I am trying to solve this problem
A number when divided by a divisor leaves a remainder of 24. When twice the original number is divided by the same divisor, the remainder is 11. What is the value of the divisor?
I have established two relations here but dont know how to proceed , any suggestions would be appreciated .
$x= dq + 24 $ where d=divisor
$2x= dk + 11 $ where d=divisor