Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

In my reading, it says that the function $x/\log x$ approaches infinity slower than $x$ (I got that bit), but then it says that it also approaches it faster that the functions $x^{1-d}$, where $d$ is any positive integer, as (apparently) evidenced by the limit of $(\log x)/x^d$ approaching $0$. That's where I get lost. From my interpretation, the functions $x^{1-d}$ are $x^0$, $x^{-1}$, $x^{-2}$, etc.. These approach $0$, not infinity (excluding $x^0$, obviously), so DUH, of course $x/\log x$ approaches infinity faster! Or am I missing something?

share|improve this question
    
reading what, exactly? The first part works when $0 < d < 1$ is not an integer at all. Instead of the letter $d,$ it is more common to use the Greek $\delta$ for this. –  Will Jagy Jul 17 '12 at 19:03
add comment

1 Answer

It should say "real number 0 < d < 1" rather than "positive integer d".

share|improve this answer
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.