Evaluating the contour integral: $\oint_C \frac{\sin 2z}{(6z-\pi)^3}dz$

I am trying to evaluate the following integral, but don't know how to take the coefficient of $z$ out of the parenthesis to get it into the Cauchy integral form. Any help is appreciated.

$$\oint_C \frac{\sin 2z}{(6z-\pi)^3}dz$$

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Do you mean as in $$6^3\left(z-\frac{\pi}{6}\right)^3?$$