Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

I am trying to evaluate the following integral, but don't know how to take the coefficient of $z$ out of the parenthesis to get it into the Cauchy integral form. Any help is appreciated.

$$ \oint_C \frac{\sin 2z}{(6z-\pi)^3}dz$$

share|improve this question
add comment

1 Answer

Do you mean as in $$6^3\left(z-\frac{\pi}{6}\right)^3?$$

share|improve this answer
    
Hmm. I tried expanding it out and got into a mess, and didn't realize it was that simple. Thanks. –  Joebevo Jul 17 '12 at 6:38
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.