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Let $\{u^k\}\subset \mathbb{R}^n$ be a sequence such that there exists a subsequence $\{u^{k_i}\}\subset \{u^k\}$ converging to $\bar{u}\in \mathbb{R}^n$.

I would like to ask when we have a stronger conclusion that $\{u^k\}$ converges to $\bar{u}$. For example, if $\{\|u^k-\bar{u}\|\}$ is monotonically decreasing then $\{u^k\}$ converges to $\bar{u}$.

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A Cauchy sequence converges if and only if it has a convergent subsequence. – Arturo Magidin Jul 17 '12 at 5:56
Dear Arturo Magidin. Since $\{u^k\}\subset\mathbb{R}^n$, $\{u^k\}$ is a Cauchy sequence iff it is convergent. – blindman Jul 17 '12 at 6:02
Are you asking that, if a sequence has a convergent subsequence, then the main sequence converges? – Mhenni Benghorbal Jul 17 '12 at 6:09
@Mhenni Benghobal. I would like to find some sufficient conditions for the sequence $\{u^k\}$ to be convergent in the case $\{u^k\}$ has a convergent subsequence. – blindman Jul 17 '12 at 6:16
up vote 2 down vote accepted

You need to assume that the main sequence is Cauchy, and by the following lemma, your sequence converges:

Let $(X,d)$ be a metric space, and let $(a_k)$ be a Cauchy sequence in $X$. Then $(a_k)$ converges iff $(a_k)$ has a convergent subsequence.

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in our case $\{u^k\}\subset \mathbb{R}^n$, we don't consider in a general metric space. – blindman Jul 17 '12 at 6:33
Yes, but since $\mathbb{R}^n$ is in fact a metric space, the result applies. – KReiser Jul 17 '12 at 6:39
Yes, R^n is a metric space. – Mhenni Benghorbal Jul 17 '12 at 6:45
@KReiser, I understand completely what you mentioned, but I would like to find more properties of the sequence $\{u^k\}\subset \mathbb{R}^n$ to guarantee $\{u^k\}$ to be convegent in the case it has a convergent subsequence. – blindman Jul 17 '12 at 6:54
Any supposed technique that will show the result you ask for will necessarily prove that the sequence is Cauchy. Under most circumstances, checking that a sequence is Cauchy is usually easy enough to do. Perhaps if you have a specific example in mind where the check is hard, you could post it? – KReiser Jul 17 '12 at 8:11

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