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A satellite is moving in circular motion round a planet.

From the physics we know that

$$\Sigma F_r = ma_r = \frac{GMm}{r^2}$$

So I wanted to find the equation for $M$ knowing also that $$v = \omega r = \frac{2\pi r}{T}$$ and

$$a_r = \frac{v^2}{r}$$

Thus,

$$ma_r = \frac{GMm}{r^2}$$ $$a_r = \frac{GM}{r^2}$$ $$\frac{v^2}{r} = \frac{GM}{r^2}$$ $$\frac{\left(\frac{2\pi r}{T}\right)^2}{r} = \frac{GM}{r^2}$$ $$\frac{\frac{4\pi^2r^2}{T^2}}{r} = \frac{GM}{r^2}$$ $$\frac{4\pi^2r^3}{T^2} = \frac{GM}{r^2}$$ $$\frac{4\pi^2r^5}{T^2} = GM$$ $$\frac{4\pi^2r^5G}{T^2} = M$$

However, this is wrong! It should be:

$$M = \frac{4\pi^2r^3}{GT^2}$$

What was my mistake in Mathematics? Please don't migrate it to physics because my misunderstanding is on math.

Note: I would be very happy if you show my mistake, instead of showing me another way to get to the equation.

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up vote 5 down vote accepted

The mistake lies in these steps:

$$\frac{\frac{4\pi^2r^2}{T^2}}{r} = \frac{GM}{r^2}$$ $$\frac{4\pi^2r^3}{T^2} = \frac{GM}{r^2}$$ $$\frac{4\pi^2r^5}{T^2} = GM$$ $$\frac{4\pi^2r^5G}{T^2} = M$$

Actually, it should have been:

$$\frac{\frac{4\pi^2r^2}{T^2}}{r} = \frac{GM}{r^2}$$ $$\frac{4\pi^2r}{T^2} = \frac{GM}{r^2}$$ $$\frac{4\pi^2r^3}{T^2} = GM$$ $$\frac{4\pi^2r^3}{GT^2} = M$$

  1. In the second step, the numerator will have $r$ and not $r^3$.
  2. In the last step, $G$ will be in the denominator.
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Oh right! It was a little confusion. Thanks! – Pichi Wuana Mar 23 at 15:40
    
You're welcome! – SchrodingersCat Mar 23 at 15:40

$\frac{4\pi^2r^2}{T^2}/r=\frac{4\pi r}{T^2}$ and G should go down not up in numerator.

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When going from $\frac{4\pi^2r^2/T^2}{r}$ to $\frac{4\pi^2r^3}{T^2}$ you added an extra factor of $r^2$; you should have canceled out an $r$ from the numerator and denominator, giving you $\frac{4\pi^2r}{T^2}$. Then when going from $\frac{4\pi^2r^5}{T^2} = GM$ to $\frac{4\pi^2r^5G}{T^2} = M$, you needed to divide each side by $G$; $G$ should be in the denominator on the left-hand side, not the numerator.,

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