# Proving $A \subset B \Rightarrow B' \subset A'$

Suppose that A is a subset of B. How can we show that B-complement is a subset of A-complement?

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What have you tried already? –  Dylan Wilson Jan 9 '11 at 3:25
tried specific exmaples, but couldn't find a general solution. –  Baha Jan 9 '11 at 3:25
A belongs to? Maybe you mean subset? –  Aryabhata Jan 9 '11 at 3:37
yes, that's what I mean –  Baha Jan 9 '11 at 14:26
Suppose $b\in B^c$. Is it possible that $b\in A$? Suppose it is, and derive a contradiction, and you should have your desired containment.
This site uses TeX markup, my specific code is $b\in B^c$ and $b\in A$. To get them to look the way they do, surround them with $signs. Here is a good list of basic symbols. – yunone Jan 9 '11 at 3:33 add comment Instead of using a proof by contradiction,$b\in B^c \implies b \notin A$since$A \subset B$hence$b \in A^c$which implies the result. The key here being that for all$x$, either$x\in X$or$x\in X^c\$.