Tell me more ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

$f_n(x):[0,1]\rightarrow \mathbb{R}$ defined by $$f_n(x)= \sin(n\pi x)$$ if $x\in [0,1/n]$, and $$f_n(x)=0$$ if $x\in (1/n,1]$ Then

  1. It Does not converge pointwise.

  2. It converge pointwise but the limit is not continous.

  3. It converge pointwise but not uniformly.

  4. It converge uniformly.

well, limit function is $0$ clearly, clearly $\sup|f_n(x)-0|\rightarrow 0$ as $n\rightarrow \infty$ and $x\in [0,1]$ so, it converges uniformly to $0$ am I right? so in my guess, 4 is only correct.

share|improve this question

1 Answer

Here is a hint for your problem:

Note that given an $n$ you will always be able to find a $c \in [0, \frac{1}{n}]$ such that $f_n(c) = 1$.

share|improve this answer
So,I guess option $3$ is the correct choice. – learner Apr 3 at 13:01

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.