Tell me more ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

A paper I am working on starts with the choice of three parameters $n$, $l$, and $e$. These then determine three more parameters $r_a$, $r_b$, and $\epsilon$.

It would be more useful and meaningful if I could start with $r_a$, $r_b$, and $\epsilon$ and solve for $n$, $l$, and $e$. When the problem is simplified, its found that n has the following dependence:

$$ r_a^{(2-n)}+\epsilon r_a^2 = r_b^{(2-n)}+\epsilon r_b^2 $$

Is there anyway that one can solve for $n$? I have rewritten the equation in terms of the Lambert-W function, $W(z)e^{W(z)}=z$, however I'm still unable to find a closed form solution that can be written as a function $n=f(r_a,r_b,\epsilon)$, even one that includes the Lambert-W function. I feel like the W function was key, but that I am still missing something.

I guess my end-game is that if I can find such a function, any terms including W could be expanded using some iterative method for approximating W.

Additional thoughts: $r_b < r_a$ and both $r_{a,b} > 0$

share|improve this question
You have $\epsilon = \dfrac{r_b^{(2-n)} - r_a^{(2-n)}}{r_a^2-r_b^2}$ so it should not be difficult to find a solution for $n$ using numerical methods (assuming $n$ can take any real value) – Henry Jul 5 '12 at 19:00

Know someone who can answer? Share a link to this question via email, Google+, Twitter, or Facebook.

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Browse other questions tagged or ask your own question.