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I've been trying to prove this statement the whole weekend...

Let $g_1,\dots,g_m$ be concave functions on $\mathbb{R}^n$. Prove that the set $S=\{x:g_i(x)\geq{0},\ i=1,\dots,m\}$ is convex.

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1 Answer 1

up vote 6 down vote accepted

Take $x,y\in S$ and $a\in [0,1]$ and $i\in\{1,\dots,m\}$. Then by concavity of $g_i$, $$g_i(ax+(1-a)y)\geq ag_i(x)+(1-a)g_i(y).$$ This quantity is non-negative, because so are $a$, $1-a$, $g_i(x)$ and $g_i(y)$. We conclude that $ax+(1-a)y\in S$, hence $S$ is convex.

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Oh! Ok I see it now. I just somehow couldn't see the logical leap from g's concavity to x and y's convexity. Thank you so much! –  Jeff Jul 2 '12 at 9:54
You are welcome. –  Davide Giraudo Jul 2 '12 at 10:00

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