# Is $M$ the midpoint of this line?

$${{\bullet\!\!\! -\!\!\!-\!\!\!-\!\!\!-\!\!\!-\!\!\!\bullet\!\!\! -\!\!\!-\!\!\!-\!\!\!-\!\!\!-\!\!\!\bullet}\atop O \;\quad\quad M\quad\quad\; P}$$

Given that $OM = x + 8$, $MP = 2x - 6$, $OP = 44$, is $M$ the midpoint of $OP$?

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We have that $$OM + MP = OP$$ so $$(x+8)+(2x-6)=3x+2=44$$ $$3x=42$$ $$x=14$$ Therefore $OM=x+8=22$ and $MP=2\cdot 14-6=28-6=22$. Because the lengths of $OM$ and $MP$ are equal, $M$ is the midpoint of the line $OP$.

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HINT $$OM + MP = OP$$ Move your mouse over the gray area for the complete solution.
Note that $$OM + MP = OP$$ and hence we get that $3x+2 = 44 \implies x =14$. Hence, $OM = 14 + 8 = 22 = \dfrac{44}2 = \dfrac{OP}2$. Hence, $M$ is indeed the midpoint.
@Michael Since $M$ is a point on the line, we have the distance from $O$ to $P$ is nothing but the sum of the distance from $O$ to $M$ and then from $M$ to $P$. –  user17762 Jun 28 '12 at 2:21
If $PQR$ are along a line and $Q$ is inbetween $P$ and $R$, then $PQ + QR = PR$. If this is the case, then we get that $$x^2 + 3 + 4 + 2x = 15 \implies x^2 + 2x -8 = 0$$ Now can you find $x$, keeping in mind that $QR \geq 0$. –  user17762 Jun 28 '12 at 2:29