# Triangle and altitudes

I need help with the following problem.

Given an acute triangle $ABC$. $BB_1$ and $CC_1$ are the altitudes. If $\frac{B_1C_1} {C_1B} = \sqrt 2$ and $\angle ACB=75^{\circ}$, find the angles $\angle ABC$ and $\angle BAC$

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What have you tried or thought about so far? –  Zev Chonoles Jun 22 '12 at 18:57
(-1) No efforts... once again –  Norbert Jun 22 '12 at 19:12
No efforts? How do you know that? I have been trying to solve it for a few hours already... –  Adam Jun 22 '12 at 19:25
Actually, I've just found $\angle BAC= 45$ and $\angle ABC=60$. Could anyone confirm it? –  Adam Jun 22 '12 at 19:27
Well that's better –  Norbert Jun 22 '12 at 19:32