Find 6th roots of $$\frac{2i}{1+i}$$
$$\frac{2i}{1+i}=\frac{2e^{i\pi/2}}{\sqrt 2 e^{i \pi/4}}=\sqrt 2 e^{i \pi/4}$$
Now if I set $z^{1/6}=\sqrt 2 e^{i \pi/4}$ and knowing the fact that the roots are distibuted equality with an angle $k\pi/3$ for $k=1,2,3,4,5,6$ I get the answer to be:
$$2^{1/12}( \cos(\pi/24 + k\pi/3)+i\sin(\pi/24 + k\pi/3))$$
Is this correct?