Let $n$ be a positive integer and $p$ be a prime. Find the greatest common factor of $\binom{p^n}{1}, \binom{p^n}{2},...,\binom{p^n}{p^n-1}$.
Progress: We know that for any given $n$ and $k$ in $\binom{p^n}{k}$, $$ \sum_{m = 1}^\infty \biggl \lfloor \dfrac{p^n}{p^m} \biggr \rfloor \geq \sum_{m=1}^\infty \biggl [\biggl \lfloor \dfrac{p^n-k}{p^m} \biggr \rfloor + \biggl \lfloor \dfrac{n}{p^m} \biggr \rfloor \biggr]$$ because of the inequality $\displaystyle \lfloor x+y \rfloor \geq \lfloor x \rfloor + \lfloor y \rfloor$. But this doesn't prove that each combination has to be divisible by $p^n$ because some may have no factors of $p$. So I am stuck here.