Let $k$ be a field and $R=k[x,y,z]$, let $M=R/\langle x^2,xy,yz^2,y^4\rangle$ be $R$-module, how can we compute the left free resolution of $M$, and also the betti numbers of this resolution?
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The first step is to plug your module into Macaulay2. As far as I understand from the official tutorial on modules in Macaulay2, the way to make modules is as kernels or cokernels of linear maps given by matrices. Thus, for example you get:
The first three commands are self-explanatory. The fourth computes a free resolution of the R-module M, and its output looks like:
So in partiuclar, we have that the resolution is $M\leftarrow R\leftarrow R^{\oplus 4}\leftarrow R^{\oplus 4}\leftarrow R\leftarrow 0$. If you want to see what the individual maps (differentials) are in terms of matrices, you call the
The last command, betti, outputs something called a betti talli, which looks something like this:
The first row are the indices of a free resolution $M\leftarrow F_0\leftarrow F_1\leftarrow F_2\leftarrow F_3\leftarrow 0$, where the $F_i$ are free modules. The second row are the total betti numbers, that is, the ranks of the free modules. Further, we have matrix $(\gamma_{ij})$ with a column for each module in the resolution, and as many rows are necessary to encode the graded betti numbers according to the scheme $\gamma_{ik}=\beta_{i,i+k}$ where $\beta_{ij}$ is the degree $j$ graded betti number for the $i^\text{th}$ free module. |
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