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Here I am stuck in solving Fourier transform and the funny part is that I am stuck in the basics, in the complex part. I hope someone can help me solve this part.

$$ 3 + 3 ( \cos \frac{4\pi}3 + j \sin \frac{4\pi}3 ) - 6 ( \cos\frac{4\pi}3 - j \sin \frac{4\pi}3 ) \over -16 \pi^2$$

If anybody is intrested in the question let me know.

Fourier transform:

another question is: how can I find the Fourier transform of $$f(t) = e^{3t} ( H(t+2) - H(t) )$$

I will highly appreciate the steps of the answers.


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Would you mind saying what the function you're trying to Fourier transform is, please, and the process which led you to the algebra you're stuck on? – Neal May 28 '12 at 16:08
I am in the process of trying to understand fourier transform , new in it . so i found this question given a periodic function with period 3 : f(t) = 0 if -1<= t < 0 t if 0<= t < 1 2-t if 1<= t < 2 so 1 sketch the graph of f(t) on the interval [-5, 7] calculate the fourier coefficient sketch the graph of g(t) calculate the complex frourier coeffiecients Fn of f(t) calculate and simplify the real coefficients a2 and b2 , i am trying to find out a2 and b2 now which led me to seek for help – gargoor May 28 '12 at 18:26
given a periodic function with period 3 : f(t) = (0 if -1<= t < 0) (t if 0<= t < 1) (2-t if 1<= t < 2) – gargoor May 28 '12 at 20:06

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