# Expression for function f:(a+bi) -> (a^2+b)+ai

Let $f:(a+bi) \to (a^2+b)+ai$

Is there an expression for f such that does not use functions Re and Im?

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You can try substituting in $a = \frac{1}{2}(z + \bar z)$ and $b = \frac{1}{2i}(z - \bar z)$ and seeing if your expression simplifies. –  Rahul Dec 21 '10 at 17:23
My bet would be no, but I wouldn't know how to prove it. –  Noldorin Dec 21 '10 at 17:25
Following Rahul's suggestion, $f(z) = \frac14 z^2 + \frac12 |z|^2 + \frac14 \overline{z}^2 + i\overline{z}$. –  Dave Radcliffe Dec 21 '10 at 18:09
Seems like using $\overline{z}$ is cheating if we are not allowed Im. –  Ross Millikan Dec 21 '10 at 18:13
What is an "expression"? If you allow $\overline{z}$, then you can express Re and Im in terms of it as Rahul writes. If you allow $|z|$ then $|z|^2/z=\overline{z}$ for all nonzero $z$. If you limit yourself to analytic functions, then the answer is "no" as lhf explains. –  David Speyer Dec 21 '10 at 20:56