# Power Series $0^{0}$

My textbook explains that the power series: $\sum_{n=0}^{\infty} x^{n}/n!$ converges for $x=0$ because the terms of the series get the value 0.

My problem with this argument is the first term, which is $0^{0}$. But this is undefined? Someone who can explain this?

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The first term is taken to be $1$ for all $x$. A less compact way of writing the series is $$1 + \sum_{n=1}^{\infty}\frac{x^n}{n!},$$ since it is the Taylor series of $e^x$, so the constant term is $f(0) = e^0 = 1$. –  Arturo Magidin May 27 '12 at 22:07
This convention is nearly universally observed to prevent the awkwardness Arturo has described. –  ncmathsadist May 27 '12 at 22:11
Great! I found the errata of the book and it was a mistake. –  characters May 27 '12 at 22:12
possible duplicate of Zero to the zero power - Is $0^0=1$? –  Nate Eldredge Jun 8 '13 at 20:18

In the context described in the question, it is a convention that $0^0 = 1$.
In a power series, $x^n$ is not exponentiation operation on real numbers. Instead, it uses a different exponentiation operation; e.g. repeated multiplication suffices for this purpose. Therefore, $x^0=1$ identically.
Of course, most people don't like to pay attention to this level of detail in syntax, so they just treat $x^0=1$ when $x=0$ as a convention.