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I have a measurement from which I want to deduct the value of a physical size (velocity). The theoretical equation is $$ A\frac{(b+vt)^2}{(c-vt)^2} $$

Where $A$, $b$ and $c$ are all known sizes, $t$ is the time variable and $v$ is the wanted size. Which curve should I approximate the measured data in order to find $v$?

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up vote 1 down vote accepted

$y_t = A \dfrac{(b+vt)^2}{(c-vt)^2}$

$\sqrt {y_t/A} = \dfrac{b+vt}{c-vt}$

Let $u_t = \sqrt {y_t/A}$

$vt(1+u_t) = cu_t-b$

Can you take it from here?

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