I am trying to find the smallest multiple of $5$ that have rest $2$ when divided by $3$ and by $4$.
I know that $5x-2=3q$ and $5x-2=4p$, by the Euclidean division. Then I give values to $x$ until I find a multiple of $3$ and $4$ simultaniosly. I found $x=10$. I would like to know if there is another way to show this!