Determine variance & mean

I am not sure how to determine the variance and mean for the following equation system. I'd greatly appreciate your help!

$f_\xi(x) = \left\{ \begin{array}{l l} 10k_1x & \quad \text{for$0<x<1$}\\ 0 & \quad \text{for other}\\ \end{array} \right.$

$f_\eta(x) = \left\{ \begin{array}{l l} 4k_2x & \quad \text{for$0<x<1$}\\ 4k_2(2-x) & \quad \text{for$1\leq x<2$}\\ \end{array} \right.$

I have determined the following:

$k_1 = \frac{1}{5}$

$k_2=\frac{2}{7}$

... and I believe to have found their individual variance and mean:

$E_\xi(x)=\frac{2}{3}$

$V_\xi(x)=\frac{1}{18}$

$E_\eta(x)=\frac{22}{21}$

$V_\eta(x)=\frac{145}{882}$

Now to the gist of my question: how do I calculate the variance and the mean for $10\xi+2\eta$? Thank you!

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Since it is homework, I will not calculate mean, variance apart from giving the odd hint. But for the second, it should be obvious by symmetry that the mean is $1$. If you did it by integration, there was a slip. For the variance, often the easiest thing is to use $E(X^2)-(E(X))^2$. – André Nicolas May 20 '12 at 18:15

Let $X$ and $Y$ be random variables, and let $a$ and $b$ be constants.
We have $E(aX+bY)=aE(X)+bE(Y)$.
If $X$ and $Y$ are independent then $\text{Var}(aX+bY)=a^2\text{Var}(X)+b^2\text{Var}(Y)$.
(If $X$ and $Y$ are not independent, one can say little about the variance of the linear combination.)