Sign up ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

Possible Duplicate:
Different methods to compute $\sum\limits_{n=1}^\infty \frac{1}{n^2}$
Does $\sum\limits_{k=1}^n 1 / k ^ 2$ converge when $n\rightarrow\infty$?

I read my book of EDP, and there appears the next serie $$\sum _{k=1} \dfrac{1}{k^2} = \dfrac{\pi^2}{6}$$ And, also, we prove that this series is equal $\frac{\pi^2}{6}$ for methods od analysis of Fourier, but...

Do you know other proof, any more simple or beautiful?

share|cite|improve this question

marked as duplicate by David Mitra, Henry, Asaf Karagila, Martin Sleziak, Nate Eldredge May 13 '12 at 20:35

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

That should be $\pi^2/6$. – David Mitra May 13 '12 at 19:31
See here – David Mitra May 13 '12 at 19:33
@Martin: This question asks for methods to calculate the sum, not to prove its convergence. This is at least how I read this question. – Asaf Karagila May 13 '12 at 19:55
@Asaf I think you' right. Although, the body is different from the title. Which explains why I thought that the OP asks about convergence only. (It's not that important now, since we found duplicates for both possible meanings.) – Martin Sleziak May 13 '12 at 19:57
The title originally said Prove that this series converges – Henry May 14 '12 at 10:05

2 Answers 2

If you just want to show it converges, then the partial sums are increasing but the whole series is bounded above by $$1+\int_1^\infty \frac{1}{x^2} dx=2$$ and below by $$\int_1^\infty \frac{1}{x^2} dx=1,$$ since $\int_{k}^{k+1} \frac{1}{x^2} dx \lt \frac{1}{k^2} \lt \int_{k-1}^{k} \frac{1}{x^2} dx$.

share|cite|improve this answer

Not the answer you're looking for? Browse other questions tagged or ask your own question.