I know that $(x - h)^2 + (y - k)^2 = 1$ is a circle, but what would the graph look like for $|x-h| + |y-k| = 1$ and why would it look like that?
- Anybody can ask a question
- Anybody can answer
- The best answers are voted up and rise to the top
It will have a graph very similar to the graph of $|x|+|y|=1$, except displaced so as to have "centre" $(h,k)$. Now you need to graph $|x|+|y|=1$. First deal with the first quadrant part. That's just $x+y=1$. Now deal with the second quadrant part. In the second quadrant, $|x|=-x$, and $|y|=y$, so we are looking at $-x+y=1$. Continue.