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On a Cartesian graph I have a point at $x = 0$ and $y = 0$. This point needs to move forward at a $30^\circ$ angle. It should travel forward at this angle for $1.75$ on the graph. What equation can I use to do this?


  • Cartesian graph point $(0, 0)$
  • Moves forward at a $30^\circ$ angle
  • Needs to travel forward at the angle $1.75$ on the graph
  • Is there an equation for this?
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I suggest you read up on trigonometry – E.O. May 7 '12 at 5:11
Thanks captain obvious. But I'm just getting back into math after a very long time. – Ash Blue May 7 '12 at 5:36
Looks like (sin( angle * pie / 180) * 1.75) worked. – Ash Blue May 7 '12 at 5:37
up vote 3 down vote accepted

There is an way to determine the coordinates of the point. I assume that you mean "moves $1.75$ units along a line in the first quadrant that makes a $30$ degree angle with the positive x-axis", or something like that.

Draw a reference right triangle enter image description here

This one is pretty sloppy... learn "SOHCAHTOA", a mnemonic device for trig ratios. Then we can say $$\cos(30) = x/1.75 $$

$$\sin(30) = y/1.75$$ And solve for x, y.

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your missing (angle * pie / 180) * 175 – Ash Blue May 15 '12 at 17:17

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