In how many ways can the letters of the word $MISSISSIPPI$ be rearranged ?
I am confused on whether it is $\dfrac{11!}{4!4!2!}$ or $\dfrac{11!}{4!4!2!}-1$
since it is given rearranged and not arranged.
In how many ways can the letters of the word $MISSISSIPPI$ be rearranged ?
I am confused on whether it is $\dfrac{11!}{4!4!2!}$ or $\dfrac{11!}{4!4!2!}-1$
since it is given rearranged and not arranged.
$$ \frac{11!}{4!4!2!} -1 $$
since $\frac{11!}{4!4!2!}$ is the total number of permutations of the letters from the word MISSISSIPPI.
Since, the word itself is not a rearrangement of itself, that's why a "-1"