Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I have a vector which takes form $\mathbf{\tilde{A}}=\mathbf{A}e^{i \theta(\mathbf{k})}$, where $\mathbf{k}$ is the frequency vector ($k^2=k_x^2 +k_y^2+k_z^2$), $i$ is unitary complex number, while $\mathbf{A}$ and $\theta$ are the vector amplitudes and phases, respectively. $\theta(\mathbf{k})$ froms a uniform random distribution within $0$ and $2\pi$, and $\mathbf{\tilde{A}}$ is also randomly distributed but has a probability distribution.

$P(A, \theta)= \frac{A}{2\pi \left | A_k \right |^2} \rm exp\left ( -\frac{A^2}{2\left | A_k \right |^2} \right ) dA d\theta $

$A$ and $\phi$ are amplitude and phase of $\mathbf{\tilde{A}(\mathbf{k})}$. ${\tilde{A}(\mathbf{k})}$ has the form: ${\tilde{A}(\mathbf{k})}=a k^{-n}$, where $a$ and $n$ are constant. I need to transform to real space by taking Fourier Transform of $\mathbf{\tilde{A}(\mathbf{k})}$.

Would you please help in this regard.

share|cite|improve this question
It seems you want the Fourier Transform, the Fast Fourier Transform is only a specific algorithm for calculating the Discrete Fourier transform. – nbubis May 3 '12 at 12:48
Yes, I want Fourier Transformation, how can I do this ? – sknandi May 4 '12 at 1:49
The displayed equation doesn't make sense. The differentials inside the exponent should probably be outside it; if you write differentials you need to have them on both sides of the equation; you haven't introduced $A$ or $A_k$, only $\mathbf A$ and $\mathbf{\tilde{A}}$; and $A_k$ doesn't occur on the left-hand side. – joriki May 4 '12 at 6:48
I have added more conditions. – sknandi May 4 '12 at 14:14

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Browse other questions tagged or ask your own question.