# Eigenvalues of $A$ compared to $A^H$

How are the eigenvalues of $A^H$ related to the eigenvalues of $A$?

Here $A^H$ is the conjugate transpose of $A$

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 1. Please edit your question so it is self-contained (and does not rely on reading the title to make sense). 2. 33 percent acceptance rate? You don't like the answers you are getting on this site? – Gerry Myerson May 2 '12 at 1:50 There's a bug with my account that is preventing me from upvoting answers! :( I don't know how to resolve that issue... – quantum May 2 '12 at 2:18 Thanks for the heads up. I wasn't sure what the "accept rate" meant. I've remedied that. – quantum May 2 '12 at 2:23 You can contact moderators via team+math@stackexchange.com with account problems. – Gerry Myerson May 2 '12 at 3:20 Yup I just did, thanks. – quantum May 2 '12 at 3:20
Hint: For a matrix $X$, the determinant $det(X^H)=\overline{det(X)}$ where the overline indicates complex conjugation.
Examine $det((I\lambda-A)^H)$