# basic vector being hermitian

If the space has a mixed metric signature, not all the basis vectors are Hermitian. Nevertheless, they are defined to be self-adjoint under reversion. The vector transpose conjugate is, therefore, not necessarily the same as the Hermitian conjugate of its matrix representation. This distinction becomes important when considering Lorentz transformations in Minkowski Space. (Classical Mechanics - J. Michael Finn)

What does "basis vectors being Hermitian" mean?

And how can vector transpose conjugate differ from hermitian conjugate?

Thanks.

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Could you give a reference for that sentence? I'm curious too. –  matgaio May 1 '12 at 3:32
@matgaio I added the reference in the question. –  user27515 May 1 '12 at 3:38
If would be not too much, could you point the page? I'm trying to find this on the book (on the preview on amazon). –  matgaio May 1 '12 at 3:49
@matgaio Page 60. Thank you very much! –  user27515 May 1 '12 at 3:52
Cross-posted to physics.SE. Please indicate cross-posts; else you're wasting everyone's time. –  joriki May 1 '12 at 6:52
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