Why does dust gather in corners?

Question

I've noticed when sweeping the floor that dust gathers particularly in the corners. I assume there is a fluid mechanics reason for this. Does anyone know what it is?

---

Edit: No, really, this is a mathematical question. Air blows around the room, which constitutes a vector field. Let's say it blows through a square room with doors near bottom-left and top-right. Air blows from bottom-left to top-right.

There are dust particles in the room, let's say uniformly distributed at first. But after application of this flow they are not uniformly distributed. They pile in the corners. Maybe that's because vortices form more in the corners, maybe some other reason.

It's not because of where I start sweeping.

It is a physics question, but obviously knowledge of Newtonian mechanics won't solve it. It comes down to fluid flow and vector fields, which is math.

Answer 1

Consider the life of a single dust particle that randomly gets kicked up into the air, at which point it floats around for a while before being deposited on the floor again. One (very) simple model of this process might be as follows:

1) the probability of the particle getting kicked up in 1 second increases with the airspeed at it's location, and

2) once it's in the air, where it falls is random.

Then one would expect the particle to spend more time on the ground where the airspeed is low, and less where the airspeed is high, therefore accumulating in low-speed locations. If this model is legit, the question becomes "why does the air move slower in corners?"

Empirically, (at least from walking around my apartment) it seems that the airflow is indeed slower in the corners, so this is a good sanity-check.

To really do this justice, you'd have to consider the full Navier-stokes equations, but those are hard, so lets consider a simplified model. Suppose the flow is an incompressible, slow, pressure-driven flow with a few sources and sinks (air conditioner, cracks under the door, etc), and no-flow boundary conditions at the walls. In this case, the pressure field should solve the Laplace equation, which we have some intuition about it as some sort of smooth rubber surface trying to be "as flat as possible".

The no-flow condition means that the normal derivative of the pressure at a wall is zero. Now consider a corner between one wall along x=0, and another wall along y=0. If we are near enough to the corner, we expect to be within the realm of influence of both walls, so we expect both derivatives dP/dx and dP/dy to be small, since they are zero at the y=0 and x=0 walls respectively. Therefore the pressure gradient is small, so the velocity is small in the corner, as expected.

Summary: a simple particle model predicts dust will accumulate where the air is moving slowly, and a simple pressure-driven flow model predicts flow to be slow near corners. Whether these models are legit or not is worthy of debate, but they do predict the right behavior in this case.

Answer 2

Air flow in a room will change direction from time to time. (Just the simple act of walking through the room in random directions will shift the air flow.)

The dust particle will be carried in the direction of the air current each time.

Eventually the dust particle will hit a wall and can obviously be carried no further in that direction.

New air currents, in slightly different directions, will then carry the dust particle in the direction of other walls. Because the dust particle is next to the wall, it will be difficult to create an air current that will move the dust particle in a direction 180 degrees in the opposite direction; therefore, the air current will have a tendency to move in the direction of one of the two perpendicular walls (assuming a square room for example's sake).

The interplay of air currents will continue to push the dust particle back and forth between the two perpendicular walls into it eventually arrives in the corner. This will happen because the closer the dust particle gets to the corner (as when it is pushed directly against a wall), the surface area available to capture air currents from the general direction of the corner DECREASES, while the sufrace area available to capture air currents from the perpendicular corner INCREASES. To say another way, the ability to capture an air current that carries the dust particle 180 degrees away from the corner exponentially decreases the closer it gets closer to the corner, while the ability to capture an air current that carries the dust particle 180 degrees towards the corner exponentially increases as it gets closer to the corner.

EVERYTHING in life is a matter of mathematics. There is not an organic or inorganic process anywhere in the known universe that can not be illustrated by mathematics (of course, there are many processes we do not yet know HOW to quantify mathematically, but that is a limitation on our part; not within the inherent reach of mathematics to explain it).

Okay, that makes for an interesting Saturday morning ... cheers.

Answer 3

First, we must assume a more or less constant airflow in the room, for as everyone knows,in a room that is closed up for a long time with no airflow, dust accumulates evenly throughout the room. The simplest air flow type is random. Like water, or anything tbat flows, air flows through the path of least resistance. For air, the path of least resistance is a straight line. Resistance to flow is proportional to the angular change of direction produced by an obstacle; in this case a corner, which does not neccessarily imply a 90 degree corner. There are two types of corners: inside corners (less than 180 degrees and outside corners (greater than 180 degrees). Outside corners do not gather dust, simply because they do not force the air flow to change its direction. Inside corners, however present a physical barrier to straight-line air flow. The smaller the angle of deflection, the greater the resistance. The air simply avoids the highly flow resistant corner by curving around it. In doing so, it loses some of its energy, slowing its flowrate or speed. Of course, some of the air particles pass closer to the corner than others. The closer particles have to turn more sharply to avoid the black hole of the corner, thus slowing down more, thus losing more of their ability to hold a dust particle aloft, thus losing more dust particles before returning to the (assumed) random air flow of the room. In a simple rectangular or square room, this action results in dusty corners. This is the simplest and least technical answer I can think of. Such things as Navier-stokes equations, Laplace equations and pressure derivatives have their place, but are superflous, irrelevant overkill for answering such a simple question. "KISS" always applies. If you want a solution to the dusty corner problem (and seeking the cause of a problem is, after all, the first step in seeking a solution), simply place a contantly running vaccumn inlet in each corner with the (filtered) outlet in the center of the room, directed in all directions, and you will have constantly self-dusting corners. Then, (not so simply) eliminate all dust generators and dust attractors, and replace all objects that have inside corners (or modify them so that they have inside curves instead), and you will have a constantly self-dusting room. However, you should not complain if, upon enterimg this room, you friends declare, "This room really sucks!". I hope this clears the air (and the corners, of course).

Answer 4

If there is a net airflow in any particular direction at floor-level for any reason (doors/windows/radiators etc.), then the dust will tend to accumulate in the corner that is furthest 'down-stream'.