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Am I right that conjugacy classes of group $A_n$ can be obtained from conjugacy classes of $S_n$ (which are in correspondence with Young diagrams). If class $$C(h)=\{\sigma h {\sigma}^{-1}|\sigma\in S_n\}$$ contains independent cycles of only odd length and length of all cycles are different then $C(h)$ in $A_n$ split to two classes $$C_1(h)=\{\sigma h {\sigma}^{-1}|\sigma\in A_n\}$$ $$C_2(h)=\{\sigma \tau h {\tau}^{-1} {\sigma}^{-1}|\sigma\in A_n\}.$$ I only interested in the answer.

Thanks a lot!

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3  
answer is yes.. –  user641 Apr 18 '12 at 20:56
4  
This gives you the answer, and it is yes. –  user21436 Apr 18 '12 at 20:57
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