Is $x^x=y$ solvable for $x$?
I've been playing with this equation for a while now and can't figure out how to isolate $x$.
I've gotten to $x \ln x = \ln 5$, which seems like it would be easier to work with, but I can't figure out where to go from there.
Is it possible to solve this algebraically? If not, how can I find the value of $x$?