Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

As I'm reading a paper a paper "An Underdetermined Linear System for GPS" By Dan Kalman

And solving an equation, and I don't know how to simplify the following equation:

$$ (5.41-.095t-1)^2+(5.41-.095t-2)^2+(3.67-.067t)^2=.047^2(t-19.9)^2$$

to this one

$$0.02t^2-1.88t+43.56=0$$

share|improve this question
    
Subtract $1$ from $5.41$ and $2$ from $5.41$ in the first and second terms. Then use the rule $(a+b)^2 = a^2+2ab+b^2$. Finally, add equal terms. –  Arturo Magidin Apr 15 '12 at 3:57
2  
Is there much point in you reading this paper, if you are having such trouble with simple algebra? –  Arturo Magidin Apr 15 '12 at 4:19
    
is $$(.095t)^2$$ equals to $$(.095)^2 \cdot (t)^2$$ –  HATEM EL-AZAB Apr 15 '12 at 4:19
    
Yes. $(ab)^n = a^n b^n$. –  Arturo Magidin Apr 15 '12 at 4:21

1 Answer 1

Evaluate $.047^2$.

Within each set of parentheses, you should combine like terms—that is, add up all the terms that don't have $t$, that just have $t$, that have $t^2$, etc.

Once you've done that, each set of parentheses contains two terms being added (or subtracted). From the Distributive Property of Multiplication over Addition, $a(b+c)=ab+ac$ (the multiplication by $a$ is "distributed" to each of the terms $b$ and $c$ being added), $(a+b)(c+d)=$$(a+b)c+(a+b)d=$$ac+bc+ad+bd$ and $(a+b)^2=$$(a+b)(a+b)=$$a^2+ab+ab+b^2=$$a^2+2ab+b^2$. You can use this pattern to "expand" the rest of the squares in your equation.

Then, combine like terms on each side.

Finally, subtract the entirety of one side from both sides of the equation to get $=0$.


If the paper is essential reading and you're only stumbling over the symbolic manipulations like these, you might consider trying to use a Computer Algebra System (CAS) to help with some of the symbolic manipulation.

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.