0
$\begingroup$

As stated in the title: Why can't a closed interval $[a,b]$ on R be written as the disjoint union of countably infinite many closed intervals $[a_i,b_i]$?

$\endgroup$
3
  • $\begingroup$ Bounded both above and below? $\endgroup$ Jun 8, 2015 at 16:08
  • $\begingroup$ That's what bounded means, @TimRaczkowski In any event, what is an unbounded closed interval $[a,b]$ in $\mathbb R$? $\endgroup$ Jun 8, 2015 at 16:10
  • 1
    $\begingroup$ @ThomasAndrews Yes, I know that's what bounded means. I was making sure that the OP understood that. $\endgroup$ Jun 8, 2015 at 16:14

0

Browse other questions tagged .