# Maclaurin series of $\ln(1-x+x^2)$

Is there a closed form expression for $\text{n}^{\text{th}}$ coefficient of Maclaurin series of
$$\ln(1-x+x^2)$$

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## 1 Answer

Hint: $\ln(1-x+x^2)=\ln\left(\dfrac{1+x^3}{1+x}\right)$

Use (two times!) the expansion of $\ln(1+t)$ to conclude!

Hoping this helped,

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I want to say a "Big Thanks" to you for this hint! –  Martin Gales Apr 16 '12 at 5:47
@MartinGales: Glad it helped! –  Raymond Manzoni Apr 16 '12 at 19:51
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