Starting digits of $2^n$.

Prove that for any finite sequence of decimal digits, there exists an $n$ such that the decimal expansion of $2^n$ begins with these digits.

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hmmm... you may want to look up Poincare's recurrence theorem: en.wikipedia.org/wiki/Poincar%C3%A9_recurrence_theorem – WWright Dec 5 '10 at 21:01

Take $\log_{10} (2^n) = n \log_{10} 2$, note that $\log_{10} 2$ is irrational, and use the equidistribution theorem (or prove what you want directly using the pigeonhole principle).