Any idea how to prove that when 3D space is tiled with truncated octahedra, all vertices can be colored black and white such that no two vertices, sharing the same color, are adjacent?
The graph of a truncated octahedron is bipartite but there are space fillers with regular polygons as faces which are not bipartite.
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
4 years ago
5 months ago
Get the weekly newsletter!
see an example newsletter