# density of roots of a family of polynomials: $(1-x^2)^{v+n}$

My research has brought me to the following, very general problem.

Given a fixed, but arbitrary, natural number, $\displaystyle v$, consider the following family of polynomials: The $\displaystyle (n-1)^{th}$ derivative of

$$\displaystyle (1-x^2)^{v+n} \ \ \forall n \in \mathbb{N}$$

I would like to prove (or disprove) that the roots of this entire family of polynomials forms a dense subset of the interval $\displaystyle [0,1]$ for any value of $\displaystyle v$ (I am not interested in roots outside the interval $\displaystyle [0,1]$).

In other words, given any subinterval, $\displaystyle [a,b]$,no mater how small, at least one of these polynomials has at least one root in the interval $\displaystyle [a,b]$ (for any fixed value of $\displaystyle v$).

I realize my question is very general and will happily accept any partial solutions.

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Presumably this is related to your previous question about roots of Legendre polynomials; one technique that might be adaptable to this particular variant of the question is to prove minimal-separation results for the roots. I don't know if I've seen this even for Legendre polynomials, but it ought to be well within reach; lower bounds on the second derivative between two adjacent roots would force a separation between those roots, and those bounds might be accessible by exploiting the differential equation and the Sturm-iness... – Steven Stadnicki Dec 2 '10 at 23:35
There's a proof of the interlacing of Legendre polynomial roots in Chihara; have you by any chance been able to see the book? – J. M. Dec 3 '10 at 5:51

First note that this family of polynomials is orthogonal, on the interval $[-1,1]$, with the weight factor $(1-x^2)^{-(v+1)}$. This is not much of a surprise since the definition is very similar to that of the traditional Legendre Polynomials, which are orthogonal. Next, we use the following deep result involving orthogonal polynomials:
If $\{p_n\}$ is a family of orthogonal polynomials with roots in $[-1,1]$ and $N(a,b,n)$ represents the number of roots of $p_n$ in [$\cos(b),\cos(a)$] then
$$\lim_{n\to \infty}\frac1{n} N(a,b,n)=\frac{b-a}{\pi}$$
Thus for any small subinterval [$\cos(b),\cos(a)$], there exists $n$ sufficiently large such that $N(a,b,n)>1$ implying that the roots of these polynomials do form a dense subset of $[-1,1]$.