Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

Given two sets $ A = \{\{1\} , \{2 , 6\} \}$ and $ B = \{\{2\} , \{3\} , \{4 , 5\} \}$, what set operation can produce $$ C = \{ \{ 1 , 2 \} , \{ 1 , 3 \} , \{ 1 , 4 , 5 \} , \{ 2 , 6 , 2 \} , \{ 2 , 6 , 3 \} , \{ 2 , 6 , 4 , 5 \}\}? $$

The set $ C $ is gained by Cartesian product firstly, then two elements of each pair are combined by union. I wonder whether there is a more simple solution?

share|improve this question
9  
I’d describe $C$ simply as $\{a\cup b:a\in A\land b\in B\}$, which is of course equivalent to your $\{a\cup b:\langle a,b\rangle\in A\times B\}$. I see nothing simpler. –  Brian M. Scott Apr 1 '12 at 21:44
5  
If were allowed to make up names, I call it "Cartesian union"! –  user2468 Apr 1 '12 at 23:32
    
Thanks a lot, Brain M. Scott and J.D.. Why not Kejia Union :-D –  xando Apr 2 '12 at 17:10
add comment

1 Answer

up vote 4 down vote accepted

Converting comment to answer to get this off the Unanswered list:

I’d describe $C$ simply as $\{a\cup b:a\in A\land b\in B\}$, which is of course equivalent to your $\{a\cup b:\langle a,b\rangle \in A\times B\}$. I see nothing simpler.

share|improve this answer
    
@Brain M.Scott: Could you help me out this question: math.stackexchange.com/questions/416052/… –  Paul Jun 10 '13 at 6:13
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.