Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

If I have the group $S_{9}$ and $\sigma, \tau \in S_{9}$ where $\vert \sigma \vert = 5$ and $\vert \tau \vert = 6$ is it then possible to have $\vert \sigma \tau \vert = 30$ and $\vert \sigma \tau \vert = 12$ why/why not?

share|improve this question
3  
No element of $S_9$ has order $30$ (think about cycle types). –  Chris Eagle Mar 31 '12 at 9:33
    
Not possible because $30\ne 12$... –  lhf Apr 1 '12 at 2:59
1  
@lhf, I took it to be two separate questions, one about order 30, another about order 12. But, who knows? –  Gerry Myerson Apr 1 '12 at 6:27

1 Answer 1

up vote 3 down vote accepted

$(12345)(234657)=(1365)(247)$.

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.