# My last question was perhaps not clear!! [closed]

I previously asked a question which perhaps was a bit heavy on detail, it boils down to this - given an abelian group $G$ and two distinct elements $g_1,g_2 \in G$ is the intersection of the cyclic subgroups generated by $g_1$ and $g_2$ trivial?

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No. Let $g_1 = 2$ and $g_2 = 3$ in the group $G = \mathbb{Z}$. – JeffE Mar 28 '12 at 22:14
Instead of posting this as a new question, you can make an edit to your earlier question to mention this development. The "edit" button should be right underneath the "group theory" tag. I have now included this as an edit to your earlier question. – Zev Chonoles Mar 28 '12 at 22:15
If you are going to add finite and ask, take $\Bbb Z_8$ and $\langle 4 \rangle$ and $\langle 2 \rangle$ – user21436 Mar 28 '12 at 22:17
@Ross: I only closed the question because the OP indicated that it was an update to his earlier question. However if you think they should stand apart, I would certainly be willing to undo my actions. – Zev Chonoles Mar 28 '12 at 22:19
Also, I don't know why this is receiving downvotes - please be nice to new users! – Zev Chonoles Mar 28 '12 at 22:20