If $\cos\theta = \sin\theta$, then what is $\cos2\theta$?
I am stuck on this problem, please help.
I am stuck on this problem, please help. |
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Double angle formula: $\cos(2\theta)=\cos^2\theta-\sin^2\theta=0$. |
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The tips made above are perfectly reasonable but let me provide an algebraic answer. Using the addition formula $\cos(x+y) = \cos(x) \cos(y) - \sin(x) \sin(y)$, we know that $\cos(2x) = \cos(x+x) = \cos(x) \cos(x) - \sin(x) \sin(x)$ Does that help you now? |
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We have $\cos\theta=\sin\theta$ if $\theta=\pi/4+2k\pi$ or $\theta=3\pi/4+2k\pi$. In both of these situations, $\cos 2\theta=0$. |
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