# Algebra equation help?

\begin{align} &4\frac{1}{4}x-\frac{1}{2}x=24\\ &\frac{17}{4}x-\frac{2}{4}x=24\\ &\frac{15}{4}x=24&&\implies x=\frac{96}{14}\\ \end{align}

Can anyone help me as I am not sure I got the right answer.

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$4(1/4)=1$, not $17/4$, unless you actually meant to write $4\frac{1}{4}$ as a mixed fraction. – Dedede Mar 15 '12 at 0:28
Is that equation $4\frac14x-\frac12x=24$? – Mike Mar 15 '12 at 0:28
$4(1/4)=4\frac{1}{4}$? – Juan S Mar 15 '12 at 0:29
I edited the question using Latex, however while doing that I noticed that your last line should be $\frac{96}{15}$ and I assume one answer already points that out – Kirthi Raman Mar 15 '12 at 0:32
And the comments above is why people in college should not use mixed fractions. Ever. – Arturo Magidin Mar 15 '12 at 16:06

Assuming that "4(1/4)" is supposed to be the mixed fraction $4\!\frac{1}{4}$, then your reasoning and answer is correct, except that in the penultimate line, you wrote "$24x$" when you should just have $24$ (since you didn't multiply both sides by $x$), and that in the last line, you mean $\frac{96}{15}$, not $\frac{96}{14}$ (I assume this is just a typo). Finally, although it does not affect the correctness of your answer, you should also make sure to reduce your final result to lowest terms; neither $\frac{96}{14}$ nor $\frac{96}{15}$ is in lowest terms.