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I want to find all the co-ordinate of circle.

I know the radius of circle and considering center co-ordinate as (0,0).

So Is there any equation for finding all the co-ordinate of circle?

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You may find this post helpful:… – matt Mar 12 '12 at 7:00
{ rSin(@), rCos(@) }, will give you the points lying on the circle, for @ in (0,2*pi) – Tomarinator Mar 12 '12 at 7:08
up vote 1 down vote accepted

The equation of a circonference centered in $(0,0)$, knowing the radius $r$, is $x^2+y^2=r^2$, so the coordinates of the circle are all the points satisfying the above equation. A point inside the circle is a point for which: $x^2+y^2\le r^2$. In polar coordinates $(\rho,\phi)$, you have for the circonference, the equation: $\rho=r$ and all the points inside this circonference have the property: $\rho \le r$. In order to find all the coordinates on the circonference, you can use the equation: $y=\pm\sqrt{(r^2-x^2)}$.

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