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$W(4d^2 (1-x^2)^2) = abc^3x \sqrt{(\pi^2 (i-x^2)^2 + 16 x^2) }$

I have to find x ,i have the values of all other constants , I tried to separate it using partial fraction but I am stuck. a=3 b=4 c=7 d=9 w=19

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I'm just curious: what's the value of $\mathrm{pie}$? –  Rasmus Feb 22 '12 at 14:23
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@user1067252, I edited you question. Is that how the equation should look like? –  Pedro Tamaroff Feb 22 '12 at 14:23
    
Assuming that W is not a special function, you may want to consider the value of $x$ that makes $(\pi^2 (i-x^2)^2 + 16 x^2) >= 0$. This may give you a start. –  Emmad Kareem Feb 22 '12 at 16:00

1 Answer 1

Expanding the terms you have x^4 on the left, which will go to x^8 when you square both sides to get rid of the square root. But you will have all terms in x having an even exponent, so you can define y=x^2 to get a quartic. These have a messy solution. Without knowing the constants I don't think we can help further. You might look for rational roots using the rational root theorem

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