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Given P(A|B∪C)≥min(P(A|B),P(A|C)), prove or disprove the statement. My intuition said that the statement should be correct, however I can't think of a mathematical way of proving this statement. Any suggestion is highly appreciated

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If you are given P(A|B∪C)≥min(P(A|B),P(A|C)), what is there to prove or disprove? – Dilip Sarwate Feb 20 '12 at 21:14
up vote 2 down vote accepted


A B C Prob
0 1 0 0.2
0 0 1 0.2
1 1 1 0.6

Then $\Pr(A|B)=\Pr(A|C)=0.6/0.8 = 0.75$

but $\Pr(A|B \cup C) = 0.6/1.0 = 0.6$.

So the statement is not always true.

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thanks a lot for your answer – TearGrant Feb 20 '12 at 21:45
@TearGrant: don't forget to 1. upvote an answer (an uparrow to the left of the answer) if you like it and 2. accept it (check sign, also to the left) – Ilya Feb 22 '12 at 6:22

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