# Help with trinomial fractions [closed]

The denominator is $x-6$, and the numerator is a trinomial. I figured the trinomial out - $(x-3)(x-2)$; I'm not sure what to do after this step though.

$$\frac{x^2}{x-6} - \frac{5x+6}{x-6}$$

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What are you trying to do? It seems that your question starts in the middle of a long chain of thought, and it is quite impossible to figure out what you're speaking about. At least quote the exercise you're trying to solve. –  Henning Makholm Feb 15 '12 at 1:59
Are you trying to divide out the fraction $\frac{x^2-5x+6}{x-6}$ to get a polynomial plus a remainder of the form $\frac{a}{x-6}$? If so, you don’t want to split up the polynomial as you’ve done in the question; you want to use polynomial long division, which is also illustrated here. –  Brian M. Scott Feb 15 '12 at 3:23
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## closed as not a real question by Bill Cook, fpqc, Michael Greinecker♦, William, QuixoticSep 9 '12 at 15:27

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## 1 Answer

$x^2-(5x + 6)\neq(x -2)(x-3).$ Instead, the roots are $-1$ and $6$. So you should eventually end up with $x + 1$.

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