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My teacher gets the following: $(x^{2})^{12-k} = x^{2k-24}$

Where I get the following: $(x^{2})^{12-k} = x^{24-2k}$

I'd like to think of $2(12-k)$ as $2*12 - 2*k$ or $-2k + 24$. Why/how am I wrong?

He did the following: $x^{4k} * {a^{12-k} \over (x^{2})^{12-k}} = x^{4k} * a^{12-k} * x^{2k-24}$

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Note: $(a^b)^c = a^{bc}$. But without parenthesis, $a^{b^c}$ means $a^{(b^c)}$. Which one are you talking about, and what is the context? –  Arturo Magidin Feb 13 '12 at 4:02
    
You and your teacher are both wrong, which probably means that you have not accurately reported what your teacher actually did. –  Gerry Myerson Feb 13 '12 at 4:04
    
Sorry, clarified. –  Hum Feb 13 '12 at 4:05
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No, not clarified: corrected. If you are now accurately reporting what your teacher got, your teacher made a mistake. –  Gerry Myerson Feb 13 '12 at 4:08
2  
@GerryMyerson I think you're being a little unpleasant. I think it is quite logical to expect him to be learning $$(a^b)^c = a^{bc}$$. –  Pedro Tamaroff Feb 13 '12 at 4:18
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1 Answer

up vote 4 down vote accepted

Your first and last sentences contradict each other. I will assume that the last one is correct.

In that case, what the teacher is doing is $$ \frac1{(x^2)^{12-k}}=(x^2)^{k-12}=x^{2k-24} $$

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Ah thanks, makes a lot more sense now. Sorry, I'm tired... –  Hum Feb 13 '12 at 4:33
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